960=-12x+2x^2

Solution for 960=-12x+2x^2 equation:

960=-12x+2x^2

We move all terms to the left:

960-(-12x+2x^2)=0

We get rid of parentheses

-2x^2+12x+960=0

a = -2; b = 12; c = +960;
Δ = b2-4ac
Δ = 122-4·(-2)·960
Δ = 7824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7824}=\sqrt{16*489}=\sqrt{16}*\sqrt{489}=4\sqrt{489}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{489}}{2*-2}=\frac{-12-4\sqrt{489}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{489}}{2*-2}=\frac{-12+4\sqrt{489}}{-4}
$